import java.util.Random;

public class Exam { public static void main(String[] args){

Random random = new Random();

int x;

 for(int counter=1; 
    counter<=10;
     counter  ){
   x = 10   random.nextInt(100-10); 

System.out.println(x);
     }

} }

CodePudding user response：

Test is a given int is odd:

boolean isOdd(int number) {
    return number % 2 != 0;
}

Generate only odd numbers:

int getOddRandom(Random random) {
    random.nextInt()*2 1;
}

CodePudding user response：

To check if a number is odd in java, you can use num % 2 == 0

This returns true if it's even, false if it's odd. A simple way to isolate an odd number this way is to keep generating numbers until it hits one that matches the condition.

    public int getFirstOdd() {
        Random rand = new Random();
        int max = 10;
        int min = 1;

        while (true) {

            int randomNum = rand.nextInt((max - min)   1)   min;

            if (randomNum % 2 != 0) {
                return randomNum;
            }
        }
    }

If for some reason you want to explicitly only generate 10 numbers, just replace the while loop with a for loop.

    public int getFirstOdd() {
        Random rand = new Random();
        int max = 10;
        int min = 1;

        for (int i = 0; i < 10; i  ) {
            int num = rand.nextInt((max - min)   1)   min;
            if (num % 2 != 0) {
                return num;
            }
        }

        return -1; //If none of the numbers are odd
    }