Requirements: Before, I used instr() in Oracle to achieve the requirements, but now I want to use MySQL to achieve the same effect, and try to use the functions in MySQL to achieve it.
INSTR(A.SOME_THING.B,".",1,2)<>0 --ORACLE
CodePudding user response:
As far as I can tell, that's not that difficult for simple cases. But, as number of parameters raises, MySQL "replacement" for the same Oracle functionality gets worse.
As your code:
instr(some_thing, '.', 1, 2)
means
- search through
some_thing
- for a dot
- starting from the first position
- and find dot's second occurrence
you can't do that in a simple manner using MySQL, as you'll need a user-defined function. Something like this (source is INSTR Function - Oracle to MySQL Migration; I suggest you have a look at the whole document. I'm posting code here because links might get broken):
DELIMITER //
CREATE FUNCTION INSTR4 (p_str VARCHAR(8000), p_substr VARCHAR(255),
p_start INT, p_occurrence INT)
RETURNS INT
DETERMINISTIC
BEGIN
DECLARE v_found INT DEFAULT p_occurrence;
DECLARE v_pos INT DEFAULT p_start;
lbl:
WHILE 1=1
DO
-- Find the next occurrence
SET v_pos = LOCATE(p_substr, p_str, v_pos);
-- Nothing found
IF v_pos IS NULL OR v_pos = 0 THEN
RETURN v_pos;
END IF;
-- The required occurrence found
IF v_found = 1 THEN
LEAVE lbl;
END IF;
-- Prepare to find another one occurrence
SET v_found = v_found - 1;
SET v_pos = v_pos 1;
END WHILE;
RETURN v_pos;
END;
//
DELIMITER ;
Use it as
SELECT INSTR4('abcbcb', 'b', 3, 2);
and get 6 as a result.
CodePudding user response:
In OracleDB the code
INSTR(column, ".", 1, 2) <> 0 --ORACLE
checks does the column contains at least 2 point chars in the value.
In MySQL this can be replaced with, for example,
LENGTH(column) - LENGTH(REPLACE(column, '.', '')) >= 2