Adding numbers of the same length to a dictionary as values-CodePudding

I have a Python list:

list_1 = [1, 2, 3, 11, 22, 33, 111, 222, 3333, 2222, 1111, 333]

I want to return a dictionary whose keys are the length of the items in the list and values are lists having items of same length as key.

sample output is as shown:

Dict_1 = {1 : [1,2,3],2:[11,22,33],3:[111,222,333]...}

CodePudding user response：

You can do this:

from collections import defaultdict

lst = [1, 2, 3, 11, 22, 33, 111, 222, 3333, 2222, 1111, 333]

d = defaultdict(list)
for item in lst:
    d[len(str(item))].append(item)

print(d)

CodePudding user response：

It's prob. easier to just use the power of itertools groupby to solve this:

Notes - it's based on the assumption that the input list is orderly, meaning each item are in ordered fashion. Otherwise, it's expected to sort it first. Thanks for the comments/feedback by @S.B

The rest of formatting and putting into the outputs is left as an exercise. ;-) (Can you try it now?)

# L is your input list

from itertools import groupby

dc = dict()

for k, g in groupby(L, key=lambda x: len(str(x))):
    print(k, list(g))

Output:

1 [1, 2, 3]
2 [11, 22, 33]
3 [111, 222]
4 [3333, 2222, 1111]
3 [333]

CodePudding user response：

Dict_1 = {}

for i in list_1:
   if len(i) not in Dict_1:
      Dict_1[len(i)] = [i]
   else:
      Dict_1[len(i)].append(i)

print(Dict_1)