I am currently writing (as an exercise) a simple political calculator that checks depending on how many seats each party has, possible majorities in the parliament.
I have created an object that holds the name as key and the seats as value, like so:
let testData = {
"party1":19,
"party2":29,
"party3":10,
}
I then use Object(entries) to move the data into an array:
let testArr = Object.entries(testData);
My question is, how can I check what possible combinations there are to get more than 30(seats) without duplication ?
From the above example, none of the parties get alone over 30, so some combinations are needed.
For example - party1 party2 = 48 this is more than 30 so I save that result. But I wish to avoid having the result party2 party1 = 48, because the order of the parties is irrelevant.
CodePudding user response:
Not to prettiest but does the job, runs over the entries and then again to check them against each other. If the sum is over the threshold it will add them to the result with corresponding key.
let testData = {
party1: 19,
party2: 29,
party3: 10,
};
const combinations = new Set();
const threshold = 30;
const result = {};
Object.entries(testData).map(([key1, value1]) => {
return Object.entries(testData).map(([key2, value2]) => {
if (key1 === key2) return; // party1 === party1 do nothing
// take care of the doubles, party1 party2 === party2 party1
const key = [key1, key2].sort().join(":");
if (combinations.has(key)) return;
combinations.add(key);
// check if the sum is over the threshold
const sum = value1 value2;
if (sum > threshold) result[key] = sum;
});
});
console.log(result);
CodePudding user response:
Hint: use nested loop where outerloop handles keys and innerloop handles the values.
CodePudding user response:
let testData = {
party0: 19,
party1: 29,
party2: 10,
party3: 16,
party4: 22
};
var keys = Object.keys(testData);
var values = Object.values(testData)
for(var i = 0; i < keys.length; i ){
for(var j = 0; j < keys.length;j ){
if(i == j) continue;
if(i >= 0 && j > i)
console.log(keys[i] ":" keys[j] " = " parseInt(values[i] values[j]));
}
}