This function works with a little bit of data, but not with hundreds of rows and I wonder if I'm missing some Spreadsheet.flush()
or something of this nature.
const values = [["2022-12-31T06:00:00.000Z"],["2022-12-31T06:00:00.000Z"],["2022-12-31T06:00:00.000Z"],["2022-12-31T06:00:00.000Z"],["2022-12-31T06:00:00.000Z"],["2022-12-31T06:00:00.000Z"],["2022-12-31T06:00:00.000Z"],["2022-12-31T06:00:00.000Z"],["2022-12-31T06:00:00.000Z"],["2022-12-31T06:00:00.000Z"],["2022-12-31T06:00:00.000Z"],["2022-12-31T06:00:00.000Z"]];
function DeleteRows(sheetName, year) {
sheetName = 'Saved Budgets'//For tests
year = '2022' //For tests
var SS = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(sheetName); //Get Open Lines Sheet
var lastRow = SS.getLastRow();
var range = SS.getRange(2, 1, lastRow - 1, 1); //get range
range.sort({ column: 1, ascending: false }) // filter data descending
var firstRowToDelete = 0;
var numOfRows = 1; // starting row to be increment and become the number of rows
var values = range.getValues();//Got it for comparison
for (let a = 0; a < values.length; a ) {
let dt = new Date(values[a]).getFullYear();
if (dt == year) {
firstRowToDelete = parseInt(a);
numOfRows
}
}
if (numOfRows != 1) {
numOfRows = numOfRows - 1 // minus 1 to get the last row
SS.deleteRows(firstRowToDelete, numOfRows);
}
range.sort({ column: 1, ascending: true }) // filter data again ascending
}
CodePudding user response:
If you want to delete rows that the column "A" is year = '2022'
, firstRowToDelete = parseInt(a);
is the last index of the rows that the column "A" is year = '2022'
. And, numOfRows
is the number of rows. In this case, I'm worried that all rows that the column "A" is year = '2022'
cannot be deleted. And also, when the values are large, the rows for deleting might be over the bottom of the sheet, and/or range
of range.sort({ column: 1, ascending: true })
might be over the bottom of the sheet. I thought that this might be the reason for your issue.
If you want to remove this issue, when your script is modified, how about the following modification?
From:
for (let a = 0; a < values.length; a ) {
let dt = new Date(values[a]).getFullYear();
if (dt == year) {
firstRowToDelete = parseInt(a);
numOfRows
}
}
if (numOfRows != 1) {
numOfRows = numOfRows - 1 // minus 1 to get the last row
SS.deleteRows(firstRowToDelete, numOfRows);
}
range.sort({ column: 1, ascending: true }) // filter data again ascending
To:
for (let a = 0; a < values.length; a ) {
let dt = new Date(values[a]).getFullYear();
if (dt == year) {
if (firstRowToDelete == 0) firstRowToDelete = a 2; // Modified
numOfRows
}
}
if (numOfRows != 1) {
numOfRows = numOfRows - 1;
SS.deleteRows(firstRowToDelete, numOfRows);
}
SS.getRange(2, 1, SS.getLastRow() - 1, 1).sort({ column: 1, ascending: true }); // Modified
As another modification, how about the following modification?
From:
var values = range.getValues();//Got it for comparison
for (let a = 0; a < values.length; a ) {
let dt = new Date(values[a]).getFullYear();
if (dt == year) {
firstRowToDelete = parseInt(a);
numOfRows
}
}
if (numOfRows != 1) {
numOfRows = numOfRows - 1 // minus 1 to get the last row
SS.deleteRows(firstRowToDelete, numOfRows);
}
range.sort({ column: 1, ascending: true }) // filter data again ascending
To:
var values = range.getDisplayValues();
var numOfRows = values.filter(([a]) => new Date(a).getFullYear() == year).length;
if (numOfRows > 0) {
var firstRowToDelete = values.findIndex(([a]) => new Date(a).getFullYear() == year);
SS.deleteRows(firstRowToDelete > -1 ? firstRowToDelete 2 : firstRowToDelete, numOfRows);
}
SS.getRange(2, 1, SS.getLastRow() - 1, 1).sort({ column: 1, ascending: true });
CodePudding user response:
Try this:
NOTE: This is all based on the assumption that the values
global variable is actually a data in the spreadsheet, and you would want to remove all data with 2022.
function myFunction() {
var ss = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet(); //you can change this to specify a specific sheet
var range = ss.getRange(2,1,ss.getLastRow(), ss.getLastColumn());
var values = range.getValues();
var year = /2022/; // change this to filter other years
var newval = values.filter(x=>year.test(x) ? null : x);
console.log(newval); //to check if it populates the correct data during logging.
range.clearContent(); //clears the data based on the current range keeping the formatting.
var newrange = ss.getRange(2,1,newval.length, ss.getLastColumn()); //creates a new range based on the size of `newval`
newrange.setValues(newval);
}
Explanation:
var range = ss.getRange(2,1,ss.getLastRow(), ss.getLastColumn());
gets the current data on the spreadsheet, including the columns.- Using
var values = range.getValues();
we get a 2D array structure of the data on the spreadsheet. - Using
filter()
andtest()
method onvar newval = values.filter(x=>year.test(x) ? null : x);
using a ternary operator to test whether an array element contains the year to filter out. range.clearContent();
to delete the contents of the range.var newrange = ss.getRange(2,1,newval.length, ss.getLastColumn());
creates a new range based on the new array.newrange.setValues(newval);
sets the new value on the spreadsheet
Screenshots:
NOTE: Multiple columns in the data are for testing to see dynamic deletion even if there is additional data on the columns.
Initial data:
After running the script:
Execution duration:
References:
https://developers.google.com/apps-script/reference/spreadsheet/range#clearContent() https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/filter https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/RegExp/test