Display all numbers with a specific digit within the range (100, 1000000)-CodePudding

what's wrong with this code? It's supposed to get a digit from me, then show all the numbers between 100 & 1000000 containing that digit...

#include <stdio.h>
int main () {
int n,m;
puts("Enter your digit:\n");
scanf("%d\n", n);
int j=100;
while (j<=1000000) {
  m=10;
  if (j%m==n) {printf("%d\n",j);}
    while (j/m>=1) {
    if ((j/m)==n) {printf("%d\n",j);}
    m=m*10;}
  j =1;}
return 0;
}

CodePudding user response：

When using scanf use the '&' sign after the comma. And it is wise to avoid using '\n' inside scanf; so it should look like this: scanf("%d", &n);

CodePudding user response：

Try using this code and see how it works

#include <stdio.h>
#include <math.h>
int main () {
    int n,m;
    puts("Enter your digit:\n");
    scanf("%d", &n);
    for(int i = 1;(pow(10,i)*n)<1000000;i  )
    {
        for(int j = 0;j<(pow(10, i));j  )
        printf("%lf\t\t", ((pow(10, i)*n)) j);
        printf("\n");
    }
    return 0;
}