Return key value pair if value exists in dictionary Python-CodePudding

I have the following dictionary and list:

dict = {'one':['a','b','c','d','e','f'],
'two':['g','h','l','m'],
'three':['x','y','z'],
'four':['xx','yy']}

ls = ['a','x','c','h','l']

I need to loop through the dict values and check if the items in ls exist in dict values, if so I would like to return a new dict with key/pair values, as follows:

new_dict = {'one':['a','c'],'two':['h','l'], 'three':['x']}

CodePudding user response：

You can check overlaps with a set intersection -

new_dict = {k: list(set(v) & set(ls)) for k, v in dct.items() if (set(v) & set(ls))}

Output

{'one': ['c', 'a'], 'two': ['l', 'h'], 'three': ['x']}

CodePudding user response：

_dict = {'one':['a','b','c','d','e','f'],
'two':['g','h','l','m'],
'three':['x','y','z']}

ls = ['a','x','c','h','l']

new_dict = {k:[v for v in l if v in ls] for k,l in _dict.items()}
print(new_dict)

CodePudding user response：

First, a tip: you should never call variablke as "orange names" like int, float, dict, input, exc...

The solution:

dictt = {'one':['a','b','c','d','e','f'],
         'two':['g','h','l','m'],
         'three':['x','y','z']}

ls = ['a','x','c','h','l']

for k, v in dictt.items():
    dictt[k] = [el for el in v if el in ls]