How do I define a function whether x exists in the list in Python?-CodePudding

Define a function with following specs.

Takes two argments: x: a scaler l: a list The function will check whether x exists in the list, and print out the results if exists: yes if not: no For example:

func1(x = 12, l = [1,45,5,3]) Will produce

12 is no

def inList(x=12,l=[1,45,5,3]):
      for x in fuc1:
        if x in 1:
          print("value is in the list")
        else:
          print("value is not in the list")

CodePudding user response：

this can be a simple if statement

If x in i:
   print("It is here")
else:
   print("It is not here")

CodePudding user response：

just as simple:

def is_in_list(x, l):
    if x in l:
        print('in list')
        return
    else:
        print('not in list')

if you can't use in or you are trying to do it using loops then you can do so:

def is_in_list(x, l):
    for item in l:
        if(item == x):
            print('in list')
            return
    print('not in list')

CodePudding user response：

You can just do

["No", "Yes"][x in l]

But, as @chepner commented, it seems you are expected to write your own implementation of in, so you should avoid using it in the first place.

What about looking at each item of l and testing whether is the same or not as your target. Do you know how to test if tow items have the same value?

(BTW, avoid using l as name. It looks like a number 1 in many editors)

CodePudding user response：

You have missed the variable names up. Also, there is no need for a for loop in this case.

def inList(x=12,l=[1,45,5,3]):
    if x in l:
      print("value is in the list")
    else:
      print("value is not in the list")

CodePudding user response：

I hope this will help you:

MyList = [1,45,5,3]
x=12
def my_function(MyList , x):
# Print list
    print("Our List: ", MyList )

# Check if 'b' exists in the list or not
    if x in MyList:
        print(" value is in the list")
    else:
        print(" value is not in the list")
my_function(MyList, x)