How to print a dictionary on separate lines-CodePudding

I am attempting to use the following approach to printing the contents of a dictionary which consists of a key and multiple values for each item.


for target in items:

   print("{0}:{1}".format(target, items[target]))

The current output is the "raw" dictionary contents on a single line and I'm wondering how to print the values on separate lines instead. I have been able to print the first key as desired, but not the subsequent values.

CodePudding user response：

In order to print out all dictionary keys and values you will need to iterate the full dictionary. This is easiest to do with the .items() method . then to print the values on their own line you would need to iterate those as well.

for key, values in items.items():
    print(key, ":")
    for value in values:
        # print("  ", value) # <-- it would be more readable with some indentation 
        print(value)    # or without indentation

CodePudding user response：

If you just want more readable output I would suggest looking at pprint. You can add formatting options, but this is a basic example:

from pprint import pprint

items = {'first': {'a': 1, 'b': 2, 'c': 3},'second': {'a': 1, 'b': 2, 'c': 3}, 'third': {'a': 1, 'b': 2, 'c': 3},'fourth': {'a': 1, 'b': 2, 'c': 3}}

pprint(items)

Otherwise, you can use print in a for loop like this:

example = {'first': {'a': 1, 'b': 2, 'c': 3},'second': {'a': 1, 'b': 2, 'c': 3}, 'third': {'a': 1, 'b': 2, 'c': 3},'fourth': {'a': 1, 'b': 2, 'c': 3}}

for k, v in example.items():
    print(f"{k}: {v}")

output:

first: {'a': 1, 'b': 2, 'c': 3}
second: {'a': 1, 'b': 2, 'c': 3}
third: {'a': 1, 'b': 2, 'c': 3}
fourth: {'a': 1, 'b': 2, 'c': 3}