list of list comparing-CodePudding

I want to compare the amount of values in a list of a list. If there would be an empty list in the one of the "sub" lists, it should print "too short". If the list is long enough, meaning that it has more or 1 value in it, it should print "good". how can I do this? No library imports please.

CodePudding user response：

You can iterate through the sub-lists and check for len, or just for falsey for empty lists as Python evaluates [] as False.

lists = [[1,2],[],[3,4,5]]
for l in lists:
    if len(l) < 1:  #or just `if not l:`
        print('too short')
    else:
        print('good')

CodePudding user response：

You need to iterate each element in the list and compare the length using the len function.

Please see sample code below:

#list with one element sublist and 3 element sublist
a = [[1],[3,4,5]]
for index_length in a:
  if len(index_length) > 1:
    print("Good")
  else:
    print("too short")

Output:

Reference:

https://www.geeksforgeeks.org/how-to-get-the-number-of-elements-in-a-python-list/#:~:text=Using Len() function to,elements present in the list.