RegEx for a string that may have a version at the beginning of it-CodePudding

So, my program can accept strings like:

@vS050_A1_0002「Hello!」
@v2124_A4_005「Bye, Bye」
@k789_S3_100「Lorem imsum」

and also a string without a version number:

Vivamus blandit et nibh nec placerat.
In hac habitasse platea dictumst. Suspendisse potenti.

I tried to write a regular expression to remove the version from the string. And it came out something like this: ^[^「]*. It finds a match for the version and successfully replaces it with an empty string. But the problem is that it also works on strings without a version. That is, it deletes the entire line without the version.

So, my question is, how do I write a regular expression that only works with sentences that start with a version?

Example: A program receives 2 strings. The first @vS050_A1_0002「Hello!」 and the second Example2 string2. The result after the regular expression should be 「Hello!」 and Example2 string2.

CodePudding user response：

/^@\w /

will match @ followed by letters and numbers at the beginning of the string.

const strings = [
  '@vS050_A1_0002「Hello! ',
  '@v2124_A4_005「Bye, Bye」',
  '@k789_S3_100「Lorem imsum」',
  'Vivamus blandit et nibh nec placerat.',
  'In hac habitasse platea dictumst. Suspendisse potenti.'
];

const reg = /^@\w \s*/;

strings.forEach(s => console.log(s.replace(reg, '')));