decode the word in a way that every letter x, if it is the ith letter of the alpha starting from the-CodePudding

Problem

The code is to decode the word in such a way that For every letter x, if it is the ith letter of

the alphabet starting from the left, replace it with the ith letter starting from the right.

. For example, the string 'abcd' would be encoded to 'zyxw'.

Note: all the letters of the word are lower case alphabets

Editorial:

"abcdefghijklmnopqrstuvwxyz" is the sequence.

⚫ Here a is the fist alphabet appear in the sequence, so it will be replaced with the last

alphabet in the sequence i.e. z. ⚫b is the second alphabet from the begining in the sequence, so it will be replaced by the second last alphabet from the end i.e. y, and so on.

⚫ Here a is the fist alphabet appear in the sequence, so it will be replaced with the last

alphabet in the sequence i.e. z. ⚫b is the second alphabet from the begining in the sequence, so it will be replaced by the second last alphabet from the end i.e. y, and so on.

CodePudding user response：

If you have a list of the alphabet you find the index of that letter and then word backwords with the letter index it works, you can also modify the code to get a different encoding.

def translate_words(stringw):
alphabet = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q","r", "s", "t", "u", "v", "w", "x", "y", "z"]
newstring=""
stringw = stringw.lower()
for count, letter in enumerate(stringw):
    if letter in alphabet:
        letternum = alphabet.index(letter)
        newstring  = alphabet[25-letternum]
return newstring
print(translate_words("abcd"))

CodePudding user response：

At the risk of doing your homework for you...

def codeword(word: str) -> str:
    ABC = 'abcdefghijklmnopqrstuvwxyz'
    encoded_chars = [ABC[-ABC.index(char) - 1] for char in word.lower()]
    return ''.join(encoded_chars)


print(codeword('aaa'))
# => 'zzz'
print(codeword('abc'))
# => 'zyx'
print(codeword('stackoverflow')
# => 'hgzxpleviuold'