I've read this and that but my regex still doesn't work - it returns the first match where I expect it to return the last one.
The goal is to extract the last number before x
char and the first number after it.
My regex so far is ((\d ) ).*x(\d)
Test input: 1x2x3x4
Expected result: 2 groups? (with 3
and 4
)
Actual result: 3 groups?! (1
, 1
, 4
)
CodePudding user response:
You can capture the digits in 2 groups with an x char in between at the end of the string
(\d )x(\d )$
See a regex demo
Or without the anchor, if a lookbehind is supported:
.*(?<!\d)(\d )x(\d )