I have a list of elements mylist = [1, 2, 3, 4, 5, 6, 7, 8]
and would like to iteratively:
- copy the list
- pop the first element of the copied list
- and append it to the end of the copied list
- repeat this for the next row, etc.
Desired output:
index A B C D E F G H
0 1 2 3 4 5 6 7 8
1 2 3 4 5 6 7 8 1
2 3 4 5 6 7 8 1 2
3 4 5 6 7 8 1 2 3
4 5 6 7 8 1 2 3 4
5 6 7 8 1 2 3 4 5
6 7 8 1 2 3 4 5 6
7 8 1 2 3 4 5 6 7
I suspect a for
loop is needed but am having trouble iteratively generating rows based on the prior row.
CodePudding user response:
I think slicing
(Understanding slicing) is what you are looking for:
next_iteration = my_list[1:] [my_list[0]]
and the full loop:
output = []
for i in range(len(my_list)):
output.append(my_list[i:] my_list[:i])
CodePudding user response:
Use this numpy solution
with rolls
create by np.arange
:
mylist = [1, 2, 3, 4, 5, 6, 7, 8]
a = np.array(mylist)
rolls = np.arange(0, -8, -1)
print (rolls)
[ 0 -1 -2 -3 -4 -5 -6 -7]
df = pd.DataFrame(a[(np.arange(len(a))[:,None]-rolls) % len(a)],
columns=list('ABCDEFGH'))
print (df)
A B C D E F G H
0 1 2 3 4 5 6 7 8
1 2 3 4 5 6 7 8 1
2 3 4 5 6 7 8 1 2
3 4 5 6 7 8 1 2 3
4 5 6 7 8 1 2 3 4
5 6 7 8 1 2 3 4 5
6 7 8 1 2 3 4 5 6
7 8 1 2 3 4 5 6 7
If need loop solution (slow) is possible use numpy.roll
:
mylist = [1, 2, 3, 4, 5, 6, 7, 8]
rolls = np.arange(0, -8, -1)
df = pd.DataFrame([np.roll(mylist, i) for i in rolls],
columns=list('ABCDEFGH'))
print (df)
A B C D E F G H
0 1 2 3 4 5 6 7 8
1 2 3 4 5 6 7 8 1
2 3 4 5 6 7 8 1 2
3 4 5 6 7 8 1 2 3
4 5 6 7 8 1 2 3 4
5 6 7 8 1 2 3 4 5
6 7 8 1 2 3 4 5 6
7 8 1 2 3 4 5 6 7
CodePudding user response:
try this:
mylist = [1, 2, 3, 4, 5, 6, 7, 8]
ar = np.roll(np.array(mylist), 1)
data = [ar := np.roll(ar, -1) for _ in range(ar.size)]
df = pd.DataFrame(data, columns=[*'ABCDEFGH'])
print(df)
>>>
A B C D E F G H
0 1 2 3 4 5 6 7 8
1 2 3 4 5 6 7 8 1
2 3 4 5 6 7 8 1 2
3 4 5 6 7 8 1 2 3
4 5 6 7 8 1 2 3 4
5 6 7 8 1 2 3 4 5
6 7 8 1 2 3 4 5 6
7 8 1 2 3 4 5 6 7