import java.util.*;
import java.lang.*;
import java.io.*;
public class Main
{
public static void main (String[] args) throws java.lang.Exception
{
//your code here
Scanner sc =new Scanner(System.in);
int N=sc.nextInt();
int[] arr=new int[N];
for(int i=0;i<N;i )
arr[i]=sc.nextInt();
Solution s=new Solution();
s.Answer(arr,N);
}
}
class Solution
{
public void Answer(int [] arr,int N)
{
int p=0,ne=0,z=0,i=0;
while(i<arr.length)
{
if(arr[i]>0)
p ;
else if(arr[i]<0)
ne ;
else z ;
i ;
}
System.out.printf("%1.4f \n", p/N);
System.out.printf("%1.4f \n", ne /N);
System.out.printf("%1.4f\n ", z / N);
}
}
I have written the above code for the question Given an array of integers of size N integers, the task is to find the ratio of positive numbers, negative numbers, and zeros in the array up to four decimal places.
Examples:
Input: a[] = {2, -1, 5, 6, 0, -3}
Output: 0.5000 0.3333 0.1667
There are 3 positive, 2 negative, and 1 zero. Their ratio would be positive: 3/6 = 0.5000, negative: 2/6 = 0.3333, and zero: 1/6 = 0.1667.
I compiled the above code but it showing an Illegalformatexception. But I am not getting why it is showing like that.
I checked all syntaxes which I have used in this code. but I couldn't find that problem.
please help me in solving this plus-minus problem.
CodePudding user response:
package ddd;
import java.util.*;
public class Main
{
public static void main (String[] args) throws java.lang.Exception
{
//your code here
Scanner sc =new Scanner(System.in);
int N= sc.nextInt();
int[] arr=new int[N];
for(int i=0;i<N;i )
arr[i]=sc.nextInt();
Solution s=new Solution();
s.Answer(arr,N);
}
}
class Solution
{
public void Answer(int [] arr,int N)
{
int p=0,ne=0,z=0,i=0;
while(i<arr.length)
{
if(arr[i]>0)
p ;
else if(arr[i]<0)
ne ;
else z ;
i ;
}
System.out.printf("%1.4f \n", p/(float)N);
System.out.printf("%1.4f \n", ne/(float)N);
System.out.printf("%1.4f\n ", z/(float)N);
}
}
I think just converting N to float would solve your problem.