I have this regex code that removes leading and trailing white spaces.

regexreplaceall("^\s |\s $", ri!value, "")

However, it only removes halfwidth spaces.

Sample result process:

a) value(consist of half width spaces): " he llo "

   result: "he llo" -> correct

b) value(consist of fullwidth spaces): "　　he llo　　"

   result: "　　he llo　　" -> incorrect

Does anyone know whats the regex code for fullwidth spaces? Im Using Appian platform

Thank You everyone!

CodePudding user response：

You need to make the \s (and other) shorthand character class Unicode-aware.

Since Appian uses Java regex flavor, all you need is add the (?U) embedded flag option to the pattern:

regexreplaceall("(?U)^\s |\s $", ri!value, "")