How do I round to the thousands a division in a specific way that the top persons pay more?

The division should result in the exact total amount.

I tried this:

total = 245000
print(round(total / 3)

Expected: Person1 = 82000 Person2 = 82000 Person3 = 81000

CodePudding user response：

Divide total by 3 and round up to the next multiple of 1000. Use that for person1 and person2, then subtract those from total to give person3 the remainder.

person1 = person2 = 1000 * ceil(total / 3000)
person3 = total - person1 - person2

CodePudding user response：

Here is an approach that divides the amount by 1000, uses divmod to get the quotient and remainder when dividing the resulting amount by the number of people, then assembles a list where everyone owes 1000 times the quotient. The remainder is used to bump up some of the amounts by 1000:

def divide_amount(amount,num_people):
    amount //= 1000
    q,r = divmod(amount,num_people)
    bills = [1000*q for _ in range(num_people)]
    for i in range(r):
        bills[i]  = 1000
    return bills

print(divide_amount(245000,3)) #[82000, 82000, 81000]

CodePudding user response：

This should work for any number of people.

from math import floor

def rounddown(number, ndigits):
    return 10**-ndigits * floor(number/10**-ndigits)

total = 245000
people = 3

amounts = [rounddown(total/people, -3)   i \
    for i in [1000] * int(total/1000%people)   [0] * (people-int(total/1000%people))]