Toll-Number match in string without using regex in Python-CodePudding

sentence = "The toll-no is 800-123-2345 and 900-234-2345"

output = "800-123-2345"

I want to extract toll number which starts with the number 800.

sentence = "800-123-1243 and 900-345-6578 and 911-798-5768 and 900-1234-1234"

output = "".join([char for char in sentence if char.isdigit()])
print(output)

# output-
80012312439003456578911798576890012341234

CodePudding user response：

A non-regex way could use a simple list comprehension with string operations:

sentence = "800-123-1243 and 900-345-6578 and 911-798-5768 and 900-1234-1234"

out = [word for word in sentence.split()
       if word.startswith('800') and word.replace('-', '').isdigit()]

Output: ['800-123-1243']

If you only want the first match (if any):

out = next((word for word in sentence.split()
            if word.startswith('800') and word.replace('-', '').isdigit()),
           None)

Output: '800-123-1243'

NB. the word.replace('-', '').isdigit() is not strictly required with the provided example, but can help if the sentence is more complex and there is a risk of having words starting in 800 that are not phone numbers.

CodePudding user response：

If the pattern of the number is 800-NNN-NNNN, then you can find the first match using a simple regex:

import re

match = re.search(r'800-[0-9]{3}-[0-9]{4}', sentence)
result = match.group() if match else None