How do I create from format an ISO 8601 date with milliseconds in PHP?-CodePudding

I am trying to parse the date 2018-07-17T17:34:08.167 into a DateTimeImmutable object in my code, which I tried to do with:

\DateTimeImmutable::createFromFormat('c', $s);

However, because of the milliseconds present and the lack of the time zone, PHP returns false for this.

I then tried to create it by defining the format myself, but the problem is that T is used as a timezone abbreviation.

\DateTimeImmutable::createFromFormat('YYYY-mm-ddTHH:ii:ss.v', $s);
\DateTimeImmutable::createFromFormat('YYYY-mm-dd\\THH:ii:ss.v', $s);

I read this answer and tried wildcards, but no dice.

\DateTimeImmutable::createFromFormat('YYYY-mm-dd*HH:ii:ss.v', $s);

Anyone know how I can get this to parse?

EDIT: That moment when you spend a whole week coding in C# and then forget how to format in PHP...

CodePudding user response：

You don't have to use 4 times Y (YYYY), because Y represent year in 4 digits. Same for other "time-markers".

$s='2018-07-17T17:34:08.167';
var_dump(\DateTimeImmutable::createFromFormat('Y-m-d\TH:i:s.v', $s));

Output:

object(DateTimeImmutable)#1 (3) {
  ["date"]=>
  string(26) "2018-07-17 17:34:08.167000"
  ["timezone_type"]=>
  int(3)
  ["timezone"]=>
  string(16) "Europe/Paris"
}

CodePudding user response：

To parse a date string into a DateTimeImmutable object, you can use the createFromFormat function as you already did but you have to change the input parameter like so:

Here's an example of how you can do this:

$date_string = '2018-07-17T17:34:08.167';
$format = 'Y-m-d\TH:i:s.v';

$date = DateTimeImmutable::createFromFormat($format, $date_string);

echo $date->format('Y-m-d H:i:s.v');
// Outputs "2018-07-17 17:34:08.167"

Note that the v format specifier represents the milliseconds.