How to write a code that takes 3 inputs and prints them?-CodePudding

I apologize if this question is too basic, but i really am stuck here. I want to print 3 numbers which the user will input , but for some reason i can only take them one at a time. Is there a way the user can input all three numbers at once, without the code asking the same question three times?

using System;

namespace ConsoleApp1
{
    public class Program
    {
        public static void Main(string[] args)
        {

            Console.WriteLine("Input three values: ");

            int[] arr = new int[3];  //this is the array which will store the 3 numbers
            for (int i = 0; i < 3; i  ) //for loop that iterates three times
            {
                arr[i] = Convert.ToInt32(Console.ReadLine()); //gets user input and converts it to integer

                var value = arr[i]; //input is stored in variable 'value'


                Console.WriteLine("Here are your 3 numbers: "   value);  //output
            }

        }
    }
}

CodePudding user response：

Solution

The output line is inside the for-loop so it will print again every time you put a number. Also, the input is already stored in your array, and the "value" variable holds only a temporary value which will disappear for every loop of your for-loop and when the loop ends up. You should use a for-loop outside the ones that is in your code, which prints every value without a new line

Your code should look like this:

public static void Main()
{
    Console.WriteLine("Input three values: ");

    int[] arr = new int[3];
    for (int i = 0; i < 3; i  )
        arr[i] = Convert.ToInt32(Console.ReadLine());
    
    Console.Write("Here are your 3 numbers:");
    for(int i = 0; i < arr.Length; i  )
        Console.Write(" "   arr[i]);
    Console.WriteLine();
}

Tip

You can make your code support more than one number and display all of them in a cool way