How to get std::chrono::time_point<std::chrono::system_clock, std::chrono::seconds> from varia-CodePudding

I have declared a time_point variable and try to assign values from year month day etc. But it fails when I use sys_days. The code is something as follows.

int year=2023;
int month=1;
int day=1;
int hour=1;
int minute=1;
double second=0.000005;
std::chrono::time_point\<std::chrono::system_clock, std::chrono::seconds\> tp;
tp=sys_days{years{year} months{month} days{day}} hour minute second;

The code encountered errors, but I don't know how to fix it. Thanks for helps.

CodePudding user response：

double second = 0.000005;

This line brings questions. Your title says that you want a time_point that holds integral seconds, but here you say you want a precision of microseconds, possibly held with double representation. These can't all be true.

Assumption: You will be fine with a time_point holding an integral number of microseconds. To do this, change this line to:

int us = 5;  // 5 microseconds

Your use of some names that are in std::chrono, but without the std::chrono:: prefix, combined with variable names of the same spelling, leads to conflicts.

Assumption: declare using namespace std::chrono and rename your int variables to avoid name conflicts:

using namespace std::chrono;
int y=2023;
int m=1;
int d=1;
int h=1;
int M=1;
int us = 5;

Your time_point type now must have a different type than that stated in your title:

time_point<system_clock, microseconds> tp;

This type has a type alias in C 20 that is slightly simpler:

sys_time<microseconds> tp;

The types years, months, and days are all plural, and all std::chrono::duration types. For specifying pieces of the civil calendar, you need the singular spelling of these names: year, month, and day. These are calendrical specifiers for the civil calendar.

See What is the difference between chrono::month and chrono::months for more details on the difference between the singular and plural forms.

The expression year(y)/month(m)/day(d) creates a year_month_day. One can convert this to sys_days which creates a day-precision time_point:

sys_days{year{y}/month(m)/day(d)}

To this you can add any duration type, but not ints:

tp=sys_days{year{y}/month(m)/day(d)} hours{h} minutes{M} microseconds{us};

Unless you need to "pre declare" tp, the use of auto can simplify things greatly:

auto tp = sys_days{year{y}/month(m)/day(d)}
            hours{h}   minutes{M}   microseconds{us};