Check for multiple values with JS include-CodePudding

There is a function that checks the content of the url with window.location.href. If the URL contains a specific string it should return true:

const doesItContain = () => {
  const url = window.location.href;
  return url.includes('/items');
};

This works fine, if the url contains /items it returns true. The issue comes when it needs to check for multiple strings (multiple pages) and return true if one of them are present. For example:

const doesItContain = () => {
  const url = window.location.href;
  return url.includes('/items', '/users');
};

It returns true only for the first string in the list. Is there a way to check for both or more than one string?

CodePudding user response：

String.prototype.includes expects one argument. The other arguments are ignored.

You can use some to iterate an array of strings and check if at least one element fullfils the condition:

const doesItContain = () => {
  const url = window.location.href;
  return ['/items', '/users'].some(el => url.includes(el));
};

CodePudding user response：

You can use a regular expression, separating each of the strings to check with |.

return /\/items|\/users/.test(url);