I have an array in python made like this:

array([     18,      36,      54, ..., 9893804, 9893822, 9893840],
      dtype=int64)

I wish to obtain an array containing the "distances" bewteen ech byte...

in this case it would be: [18,18,18, ..., xxx, 18, 18]

to do that I use an ugly for i in range(len(arr))

I suspect there is a way by using np.flatnonzero(something) I could not find it.. any clue?

CodePudding user response：

How about np.diff(arr)?

arr = np.array(...)
print(np.diff(arr)) # [18 18 18 ... 18 18 18]