I have this object {country:{town:{company:{boss:{}}}}}
and this string country.town.cityhouse.major
, I need to updatr the object from the string, but keeping the previous properties and data.
{
country: {
town: {
company: {
boss: {}
},
cityhouse: {
major: {}
}
}
}
}
This is what I have so far:
function updateObj(object, path) {
const newPath = path.split('.');
let temp = {...object};
for (let i = 0; i < newPath.length; i ) {
let mid = temp[newPath[i]];
if (mid) {
temp = mid;
} else {
temp[newPath[i]] = {};
}
}
return temp;
}
const obj = { country: { town: { company: { boss: {} }}}};
const r = updateObj(obj, 'country.town.cityhouse.major');
console.log(r);
but it responds:
{
company: {
boss: {}
},
cityhouse: {},
major: {}
}
Any hint on this?
CodePudding user response:
You can clean this up a little using logical nullish assignment(??=) and a for...of
loop.
function updateObj(object, path) {
let result = { ...object };
let temp = result;
for (const k of path.split('.')) {
temp = temp[k] ??= {};
}
return result;
}
const obj = { country: { town: { company: { boss: {} } } } };
const r = updateObj(obj, 'country.town.cityhouse.major');
console.log(r);
.as-console-wrapper { max-height: 100% !important; top: 0; }
Recursive option
CodePudding user response:
This code would normally be written recursively, so you need to have a variable to hold the current scope (the path you walked on through the object) to do the job, and so i created the variable called scope
to do that job.
function updateObj(object, path) {
const newPath = path.split('.');
let temp = {...object};
let scope = temp;
for (let i = 0; i < newPath.length; i ) {
let cur = scope[newPath[i]];
if (!cur) {
scope = scope[newPath[i]] = {};
} else {
scope = cur;
}
}
return temp;
}
const obj = { country: { town: { company: { boss: {} }}}};
const r = updateObj(obj, 'country.town.cityhouse.major');
console.log(r);
This is a recursive implementation, but since it requires copying the object and passing it to the next recursive call it's not an efficient one, If i find a better more efficient implementation, I'll update this.
function updateObjRec(object, path, depth = 0) {
// base case
// if depth is equal to path length then it's over
if (depth === path.length) {
return {};
}
const cur = path[depth];
const scope = object[cur];
// here we have 2 cases
// current field already exists
update = {};
if (scope) {
update = updateObjRec({ ...scope}, path, depth 1);
} else {
update = updateObjRec({}, path, depth 1);
}
// merge with given object
object[cur] = update;
return object
}
const obj = { country: { town: { company: { boss: {} }}}};
const r = updateObjRec(obj, 'country.town.cityhouse.major'.split('.'));
console.log(r);
Update The recursive code can be rewritten this way to be more efficient
function updateObj(obj, path) {
const temp = { ...obj };
const p = path.split('.');
const updateRec = (scope, depth = 0) => {
// base case
if (depth === p.length) return;
const cur = p[depth];
if (!scope[cur]) {
scope[cur] = {};
}
updateRec(scope[cur], depth 1);
}
updateRec(temp);
return temp;
}
const obj = { country: { town: { company: { boss: {} }}}};
const r = updateObj(obj, 'country.town.cityhouse.major');
console.log(r);
CodePudding user response:
This isn't ideal, but it's a start. Basically, you're returning temp, which is the lowest layer. you want to return the root. Also when you can't find the next layer, you were creating it, but you weren't updating temp.
function updateObj(object, path) {
const newPath = path.split('.');
let temp = {...object};
const result = temp; // need to return this
for (let i = 0; i < newPath.length; i ) {
let mid = temp[newPath[i]];
if (mid) {
temp = mid;
} else {
temp[newPath[i]] = {};
temp = temp[newPath[i]] // need this
}
}
return result;
}
const obj = { country: { town: { company: { boss: {} }}}};
const r = updateObj(obj, 'country.town.cityhouse.major');
console.log(r);
CodePudding user response:
I think this is what you want to achieve
const obj = {
country: {
town: {
company: { boss: {} },
},
},
};
obj.country.town.cityhouse = {
major: {},
};
console.log(obj);