Hi I am initializing a function pointer to replace a switch statement in a boolean function. So i wanted to use a member of the structure and assign/copy address of a boolean function to this member. My later plan is to remove the switch cases and use function pointer to handle specific types (TYPE_A... etc)

//Declaration of typedef as a boolean 
typedef bool (*tone_function_t) (state_t *state, u8_t type);

//typedef structure
typedef struct node {
    tone_function_t tone;
} node_t;

bool_t tone(state_t *state, u8_t type) {
    switch (type) {
        case TYPE_A :
        case TYPE_B :
        case TYPE_C :
        case TYPE_D :
        case TYPE_E :
            return TRUE;
    }
  
    return FALSE;
}

int main(state_t *state) {
    node_t node;
    node.tone = &tone; //Compilation Error : assignment from incompatible pointer type. Am i doing any mistake here??
    return 0;
}

I am stuck with the compilation error while assigning the address of a boolean function to a member of a struct. Any clue to solve this? Also node->tone is a wrong way to initialize. Tried memcpy or malloc. It didn't really work.

Thanks in Advance!

CodePudding user response：

The tone function doesn't match the pointer type.

tone is declared to return a bool_t but the function pointer type tone_function_t returns a bool.

Change one of the two so the return types match.