Why is the curl command doesn't work in golang [duplicate]-CodePudding

I am in the trouble when I use golang to run the command curl. My version of the golang is 1.15.7. The purposed is to call a API by using POST method. This is the whole command that I want to use：

curl -X POST -H "Content-Type:application/json" -d '{"DNS_ID":"DNS_1","Domain_ID":"Domain_1","Cell_ID":"Cell_1","Device_ID":"IOT1","IMEI":"ims-208930000000003","IPv4":"60.60.0.1","IPv6":":::60.60.0.1","Slice_ID":"121312","FQDN":"test.free5gc"}' "http://192.168.1.233:5534/current" -v

And this is my code so far. I used module os/exec in golang to run the command curl.

    var body string
    var FQDN string
    var content string
    var url string

    content = "\"Content-Type:application/json\""
    url ="\"http://192.168.1.233:5534/current\""
    DomainName := "test"
    IPAddress := "60.60.0.1"

    FQDN = DomainName   ".free5gc"
    body = `"DNS_ID":"DNS_1","Domain_ID":"Domain_1","Cell_ID":"Cell_1","Device_ID":"IOT1","IMEI":"ims-208930000000003","IPv4":"`  IPAddress  `","IPv6":":::`  IPAddress  `","Slice_ID":"121312","FQDN":"` FQDN   `"`

    fmt.Println(body)

    c := exec.Command("curl","-X","POST","-H",content,"-d","'{"  body  "}'",url,"-v")

    fmt.Println(c)
    c.Stdout = os.Stdout
    c.Stderr = os.Stderr
    err := c.Run()
    if err != nil {
        fmt.Println("Error: ", err)
    }

After I build the code and run it. The whole command is correct but seems it has some problem in the part of the url. The error message is like below：

/usr/bin/curl -X POST -H "Content-Type:application/json" -d '{"DNS_ID":"DNS_1","Domain_ID":"Domain_1","Cell_ID":"Cell_1","Device_ID":"IOT1","IMEI":"ims-208930000000003","IPv4":"60.60.0.1","IPv6":":::60.60.0.1","Slice_ID":"121312","FQDN":"test.free5gc"}' "http://192.168.1.233:5534/current" -v
* Could not resolve host: "http
* Closing connection 0
curl: (6) Could not resolve host: "http
Error:  exit status 6

Also I have tried the command which is same as the above one in my VM. And the command curl can work. So I was wondering if it is the write way of the golang or not. I have no idea where the error occur. Maybe it is the "",` or ""content"" I thought. The error message seems can't recognize the whole URL. This is just mu guess. Hope guys can help me to deal with this problem. Thanks a lot

CodePudding user response：

This is happening because quotes are a way for bash to organise arguments, and since you are using Golang's os/exec package, there's no need to escape arguments prior to the command's execution (unless you are using bash in between go and the program you're trying to run):

var body string
var FQDN string
var content string
var url string

content = "Content-Type: application/json"
url = "http://192.168.1.233:5534/current"
DomainName := "test"
IPAddress := "60.60.0.1"

FQDN = DomainName   ".free5gc"
body = `"DNS_ID":"DNS_1","Domain_ID":"Domain_1","Cell_ID":"Cell_1","Device_ID":"IOT1","IMEI":"ims-208930000000003","IPv4":"`  IPAddress  `","IPv6":":::`  IPAddress  `","Slice_ID":"121312","FQDN":"` FQDN   `"`

fmt.Println(body)

c := exec.Command("curl","-X","POST","-H",content,"-d","{"  body  "}",url,"-v")

fmt.Println(c)
c.Stdout = os.Stdout
c.Stderr = os.Stderr
err := c.Run()
if err != nil {
    fmt.Println("Error: ", err)
}

tl;dr: drop the quotes, everything should start working :)