Like the Fizz buzz game. Add character in a specific number-CodePudding

The text of the problem is:

The first character is printed next to any number that is divisible by the first [user] entered number.

public static void main(String[] args){
    Scanner input = new Scanner(System.in);

    System.out.print("\nEnter 1st Number: ");
    int num = input.nextInt();

    System.out.print("\nEnter character: ");
    String c = input.nextLine();
    c = input.nextLine();

    System.out.print("\nEnter 2nd Number: ");
    int num1 = input.nextInt();

    System.out.print("\nEnter character: ");
    String c1 = input.nextLine();
    c1 = input.nextLine();

    int add = num =num;

    for (int i = 1; i <= 10; i  ){
    
        String s1 = String.valueOf(i);
        String s2 = c;
        String s3 = s1.concat(s2);
        String r1 = String.valueOf(i);
        String r2 = c1;
        String r3 = s1.concat(r2);

        System.out.println(i   s2   r2);
    }
}

CodePudding user response：

In the for loop you need to check if i is divisible by either num or num1 and print the appropriate letter if it is.

Method nextLine should be called after the call to nextInt and before a subsequent call to nextLine. Refer to Scanner is skipping nextLine() after using next() or nextFoo()?

public static void main(String[] args) {
    Scanner input = new Scanner(System.in);

    System.out.print("\nEnter 1st Number: ");
    int num = input.nextInt();
    input.nextLine();
    System.out.print("\nEnter character: ");
    String c = input.nextLine();

    System.out.print("\nEnter 2nd Number: ");
    int num1 = input.nextInt();
    input.nextLine();
    System.out.print("\nEnter character: ");
    String c1 = input.nextLine();
    for (int i = 1; i <= 10; i  ) {
        System.out.print(i);
        if (i % num == 0) {
            System.out.print(c);
        }
        if (i % num1 == 0) {
            System.out.print(c1);
        }
        System.out.println();
    }
}

Here is output from a sample run of the above code.

Enter 1st Number: 2

Enter character: &

Enter 2nd Number: 3

Enter character: *
1
2&
3*
4&
5
6&*
7
8&
9*
10&

You can also achieve the result using string concatenation, as shown in the below code.

public static void main(String[] args) {
    Scanner input = new Scanner(System.in);

    System.out.print("\nEnter 1st Number: ");
    int num = input.nextInt();
    input.nextLine();
    System.out.print("\nEnter character: ");
    String c = input.nextLine();

    System.out.print("\nEnter 2nd Number: ");
    int num1 = input.nextInt();
    input.nextLine();
    System.out.print("\nEnter character: ");
    String c1 = input.nextLine();
    String output;
    for (int i = 1; i <= 10; i  ) {
        output = ""   i;
        if (i % num == 0) {
            output  = c;
        }
        if (i % num1 == 0) {
            output  = c1;
        }
        System.out.println(output);
    }
}