How to check and list all false conditionals in if statement

I'm trying to improve my code and have better logging.

Is there an ideal way of how to tell which conditions are false in a list of conditionals?

i.e)

if(isAnimal && isCarnivore && isPlant){
 // does something
} else {
 // want to console.log all the false conditions in one console.log
}

We could write

let falseString = ""


if (!isAnimal) {
 falseString = falseString   "is not an Animal";
} 

if (!isCarnivore) {
 falseString = falseString   "is not a Carnivore";
}

if (!isPlant) {
 falseString = falseString   "is not a Plant";
}

console.log("string of false conditions" , falseString)

Then this would log a string of which conditions are false, but this seems to be a naive solution.

What is a better way to do this in JavaScript?

Thank you!

CodePudding user response：

If the variables are declared globally, you can store their names in an array and check whether it is true or not by referencing the window object:

let falseString = ""

isAnimal = true
isCarnivore = false
isPlant = false

const booleans = ['isAnimal', 'isCarnivore', 'isPlant'];

const falseBooleans = booleans.filter(e => !window[e])

console.log(falseBooleans)

CodePudding user response：

You can automate things by creating object of answers and then iterate it

// Create object for answers
const answers = {};

// Alter object with answers...
answers.isAnimal = false;
answers.isCarnivore = false;
answers.isPlant = false;
answers.isHuman = true;
answers.isMineral = false;
answers.isInsect = false;

// Define result strings
let falseAnswers = "False answers is:";
let trueAnswers = "True answers is:";

// Loop answers
for(const answer in answers) {
  answers[answer] ? trueAnswers  = ` ${answer}` : falseAnswers  = ` ${answer}`;
}

// Log
console.log(trueAnswers);
console.log(falseAnswers);