how do determine which value is the larger of the 2 values and output?-CodePudding

    int min = 20;
    int max= 150;


    System.out.println("Random value from " min " to " max  ":");

    for(int i = 0; i<2; i  ) {
    int random_int = (int)Math.floor(Math.random()*(max-min 1) min);

    System.out.println(random_int);

I get two random number in the output, but I don't know how to proceed with determining the highest value in the output?

CodePudding user response：

Replace the dots by anything you want.

    int a=...;
    int b=...;
    if (a>b) {
    ...
    }else{
    ...
    }

CodePudding user response：

You write both random values to the same variable: random_int.
Thus, once you've written the second value, the first will be gone.
In order to compare them, you need to write them to different variables like random_int_1 and random_int_2 or an array.

CodePudding user response：

Declaring an int and assigning it a value in a loop will overwrite it's value on each iteration. You're treating random_int as if its a function. If you only need 2 ints, I would ditch the loop altogether. Math.max() will return the higher of 2 values. You can use Math.max() and double up your random declaration logic like this:

System.out.println(Math.max((int)Math.floor(Math.random()*(max-min 1) min), 
                            (int)Math.floor(Math.random()*(max-min 1) min)));

Or:

Create 2 separate int variables like this:

int x = (int)Math.floor(Math.random()*(max-min 1) min); 
int y = (int)Math.floor(Math.random()*(max-min 1) min);

System.out.println( Math.max(x,y) );

Or:

int x = (int)Math.floor(Math.random()*(max-min 1) min); 
int y = (int)Math.floor(Math.random()*(max-min 1) min);

int z = Math.max(x,y);

System.out.println(z);