Removing a value from a list at a given index but returning the new list and original list-CodePudding

Writing a remove function that removes an item at a certain index and returns that list while returning the original list without the remove item. I am not sure why but when returning the new list and original list, the values are identical.

def remove(my_list, index: int):
    new_list = my_list
    new_list.remove(new_list[index])
    return new_list, my_list

my_list = ['a', 'b', 'c']
print(remove(my_list, 1)

My output is (['a', 'b', 'd'], ['a', 'b', 'd'])

What I am trying to get is (['a', 'b', 'd'], ['a', 'b', 'c', 'd'])

CodePudding user response：

You are altering my_list as well as new_list as they are technically the same thing. Try using list.copy. And as mentioned in the comments using del instead of list.remove makes more sense and is more readable:

def remove(my_list, index: int):
    new_list = my_list.copy()
    del new_list[index]
    return new_list, my_list

CodePudding user response：

You can concatenate subsets of the list that exclude the specified index and return that along with the original list:

def remove(my_list, index: int):
    return my_list[:index] my_list[index 1:],my_list