How to check if list2 has all the contents of one of list1's nested lists?-CodePudding

`list1 = [[1, 2, 3], [4, 5, 6]]
 list2 = [1 ,8 ,7 ,2, 0, 3]`

Output should say, that list2 contains all integers in one of list1's sublists.

CodePudding user response：

If there are no duplicates in either list:

s2 = set(list2)
result = any(all(e in s2 for e in sub) for sub in list1)

If there might be duplicates and you need all occurrences to appear in list2, you can use collections.Counter:

from collections import Counter

c2 = Counter(list2)
result = any(not (Counter(sub) - c2) for sub in list1)

CodePudding user response：

A version that will take duplicates into account:

from collections import Counter

list_1 = [[1, 2, 3], [4, 5, 6]]
list_2 = [1, 8, 7, 2, 0, 3]

counts = Counter(list_2)
res = any(len(Counter(e) - counts) == 0 for e in list_1)
print(res)

Output

True