Below is the string I'm operating on.
'exampleURL': ' '
'https://someurl.com'
I'm trying to clean it up using the code below. But for some reason, it doesn't work.
value_to_keep = (value_to_keep.rstrip('"').lstrip('"').rstrip("\n").lstrip("\n").rstrip("'").lstrip("'"))
I want the desired output to be
'exampleURL': 'https://someurl.com'
What is it that I'm missing here?
CodePudding user response:
Answering my own question. I have solved the issue by improving the pattern.
rstrip("' '").lstrip("' '")
Instead of one single quote, I have added two with a space. Because, that's how it is in the string.
CodePudding user response:
You can simply use the replace method and replace(" ", "")
foo = {
'exampleURL': '
https://someurl.com'.replace(" ", "")
}
print(foo['exampleURL'])
Output: https://someurl.com