I have a list of dates each with a value in MYSQL.
For each date I want to sum the value for this date and the previous 4 days.
I also want to sum the values for the start of that month to the present date. So for example:
- For 07/02/2021 sum all values from 07/02/2021 to 01/02/2021
- For 06/02/2021 sum all values from 06/02/2021 to 01/02/2021
- For 31/01/2021 sum all values from 31/01/2021 to 01/01/2021
The output should look like:
Any help would be appreciated.
Thanks
CodePudding user response:
In MYSQL 8.0 you get to use analytic/windowed functions.
SELECT
*,
SUM(value) OVER (
ORDER BY date
ROWS BETWEEN 4 PRECEEDING
AND CURRENT ROW
) AS five_day_period,
SUM(value) OVER (
PARTITION BY DATE_FORMAT(date, '%Y-%m-01')
ORDER BY date
) AS month_to_date
FROM
your_table
In the first case, it's just saying sum up the value
column, in date
order, starting from 4 rows before the current row, and ending on the current row.
In the second case, there's no ROWS BETWEEN
, and so it defaults to all the rows preceding the current row up to the current row. Instead, we add a PARTITION BY
which says to treat all rows with the same calendar month separately from any rows on a different calendar month. This, all rows before the current one
only looks back to the first row in the partition, which is the first row in the current month.
In MySQL 5.x there are no such functions. As such I would resort to correlated sub-queries.
SELECT
*,
(
SELECT SUM(value)
FROM your_table AS five_day_lookup
WHERE date >= DATE_SUB(your_table.date, INTERVAL 4 DAYS)
AND date <= your_table.date
)
AS five_day_period,
(
SELECT SUM(value)
FROM your_table AS monthly_lookup
WHERE date >= DATE(DATE_FORMAT(your_table.date, '%Y-%m-01'))
AND date <= your_table.date
)
AS month_to_date
FROM
your_table
CodePudding user response:
Here is a other way to do that:
Select
t1.`mydate` AS 'Date'
, t1.`val` AS 'Value'
, SUM( IF(t2.`mydate` >= t1.`mydate` - INTERVAL 4 DAY,t2.val,0)) AS '5 Day Period'
, SUM( IF(t2.`mydate` >= DATE_ADD(DATE_ADD(LAST_DAY(t1.`mydate` ),INTERVAL 1 DAY),INTERVAL - 1 MONTH),t2.val,0)) AS 'Month of Date'
FROM tab t1
LEFT JOIN tab t2 ON t2.`mydate`
BETWEEN LEAST( DATE_ADD(DATE_ADD(LAST_DAY(t1.`mydate` ),INTERVAL 1 DAY),INTERVAL - 1 MONTH),
t1.`mydate` - INTERVAL 4 DAY)
AND t1.`mydate`
GROUP BY t1.`mydate`
ORDER BY t1.`mydate` desc;
sample
MariaDB [bkvie]> SELECT * FROM tab;
---- ------------ ------
| id | mydate | val |
---- ------------ ------
| 1 | 2021-02-07 | 10 |
| 2 | 2021-02-06 | 30 |
| 3 | 2021-02-05 | 40 |
| 4 | 2021-02-04 | 50 |
| 5 | 2021-02-03 | 10 |
| 6 | 2021-02-02 | 20 |
| 7 | 2021-01-31 | 20 |
| 8 | 2021-01-30 | 10 |
| 9 | 2021-01-29 | 30 |
| 10 | 2021-01-28 | 40 |
| 11 | 2021-01-27 | 20 |
| 12 | 2021-01-26 | 30 |
| 13 | 2021-01-25 | 10 |
| 14 | 2021-01-24 | 40 |
| 15 | 2021-02-01 | 10 |
---- ------------ ------
15 rows in set (0.00 sec)
result
MariaDB [bkvie]> Select
-> t1.`mydate` AS 'Date'
-> , t1.`val` AS 'Value'
-> , SUM( IF(t2.`mydate` >= t1.`mydate` - INTERVAL 4 DAY,t2.val,0)) AS '5 Day Period'
-> , SUM( IF(t2.`mydate` >= DATE_ADD(DATE_ADD(LAST_DAY(t1.`mydate` ),INTERVAL 1 DAY),INTERVAL - 1 MONTH),t2.val,0)) AS 'Month of Date'
-> FROM tab t1
-> LEFT JOIN tab t2 ON t2.`mydate`
-> BETWEEN LEAST( DATE_ADD(DATE_ADD(LAST_DAY(t1.`mydate` ),INTERVAL 1 DAY),INTERVAL - 1 MONTH),
-> t1.`mydate` - INTERVAL 4 DAY)
-> AND t1.`mydate`
-> GROUP BY t1.`mydate`
-> ORDER BY t1.`mydate` desc;
------------ ------- -------------- ---------------
| Date | Value | 5 Day Period | Month of Date |
------------ ------- -------------- ---------------
| 2021-02-07 | 10 | 140 | 170 |
| 2021-02-06 | 30 | 150 | 160 |
| 2021-02-05 | 40 | 130 | 130 |
| 2021-02-04 | 50 | 110 | 90 |
| 2021-02-03 | 10 | 70 | 40 |
| 2021-02-02 | 20 | 90 | 30 |
| 2021-02-01 | 10 | 110 | 10 |
| 2021-01-31 | 20 | 120 | 200 |
| 2021-01-30 | 10 | 130 | 180 |
| 2021-01-29 | 30 | 130 | 170 |
| 2021-01-28 | 40 | 140 | 140 |
| 2021-01-27 | 20 | 100 | 100 |
| 2021-01-26 | 30 | 80 | 80 |
| 2021-01-25 | 10 | 50 | 50 |
| 2021-01-24 | 40 | 40 | 40 |
------------ ------- -------------- ---------------
15 rows in set (0.00 sec)
MariaDB [bkvie]>