Compare today´s date (local date) with another date in java-CodePudding

I am trying to implement an expiration date detector in java, for this, I need to compare the local date of the computer (today), with an expiration date (Date).

        SimpleDateFormat format = new SimpleDateFormat("dd/MM/yyyy");
        Date expirationDate;
        Temporal today;
        String expiration = ("27/12/2021"); //Expiration date of a product
        
        try {
            expirationDate = format.parse(expiration);
            today = LocalDate.now();
        } catch (ParseException e) {
            e.printStackTrace();
        }

¿How can I compare these two dates?

CodePudding user response：

If you can, use the newer java.time API for doing this sort of thing. What you are using is pretty much obsolete already. Something like this should do the trick:

public static boolean isProductExpired (String productDate, java.util.Locale theLocale) {
    java.time.format.DateTimeFormatter formatter = 
                java.time.format.DateTimeFormatter.ofPattern("dd/MM/yyyy", theLocale);
    java.time.LocalDate date1 = java.time.LocalDate.parse(productDate, formatter);
    java.time.LocalDate date2 = java.time.LocalDate.now();
    return date2.isAfter(date1);
}

To use the above method:

String productDate = "27/12/2021"; //Expiration date of a product
System.out.println(isProductExpired(productDate, java.util.Locale.ENGLISH));

CodePudding user response：

The problem has been solved.

Just convert LocalDate to Date

        SimpleDateFormat format = new SimpleDateFormat("dd/MM/yyyy");
        Date expirationDate;
        
        expirationDate = format.parse("08/12/2020");
        Date today = Date.from(LocalDate.now().atStartOfDay().atZone(ZoneId.systemDefault()).toInstant());
        
        
        if (today.before(expirationDate)) {
            //Condition Expiration
        }