If num1 or num2 don‘t equal 0-CodePudding

I am a beginner in Python and I have a question: So if I have 2 different numbers, and if either one of these numbers equals to 0 then I should return the absolute value of the number that isn‘t 0. How can I do that? I knnow how to use abs(a or b) and how to return values but I have difficulty writing the algorithm for the return the value that isn‘t 0.

Hope someone can help me, would be greatful :)

CodePudding user response：

Why not return both if one equals 0?

CodePudding user response：

abs(a or b) already does pretty much exactly what you want. Basically, a or b behaves (for numbers) like a if a != 0 else b. If you want to return None if both are 0, you can add another or None after that, meaning "return None if the absolute value is zero".

>>> f = lambda a, b: abs(a or b) or None
>>> [f(0, -4), f(3, 0), f(4, -3), f(0, 0)]
[4, 3, 4, None]

If both numbers are != 0, this will just return the first value. If you want to return None in this case, too, you can use the slightly more cryptic None if a and b else abs(a or b) or None or not (a and b) and abs(a or b) or None if you want to stick with and and or.

CodePudding user response：

what happens when both numbers are not 0? or both are 0? in this example i just returned 0:

def func1(a,b):
    #if both  number are zero
    if a == b == 0:
        return 0
    elif a == 0:
        return abs(b)
    elif b == 0:
        return abs(a)
    #if both of the numbers are not zero
    else:
        return 0