I have wrote a bit code in dartpad:
void main() {
greet('Jack');
double result = myFunction();
print(result);
}
void greet (String personToGreet) {
print('Hello, $personToGreet)
}
double myFunction () {
double pi = 3.1415926;
return pi * 2;
}
So, for myFunction part, why I can't do the same thing as I did for the greet function which changes the function type from double to void and replace the return keyword at the end and with a print statement to wrap up 'pi * 2'?
And for myFunction part in main function, can I just call this specific function directly instead of pass it into a variable and then print the variable out?
CodePudding user response:
Your function greet
expects an argument of type String
. That means you can't pass it result
, which is a double
. Instead try this:
void main() {
greet('Jack');
double result = myFunction();
print(result.toString());
}
Also you seem to be missing a closing quote around Hello