How to print even and odd integers using Numpy arange function-CodePudding

I am learner , bit stuck not getting how to print odd integers and Even integers using arange function

For Even :

Print Even integers:
arr = np.arange(5,25,2)

The above piece of line does not print even number

Output :

array([ 5,  7,  9, 11, 13, 15, 17, 19, 21, 23])

For Odd

arr = np.arange(5,25,1) 
arr

Output :

array([ 5,  6,  7,  8,  9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21,
       22, 23, 24])

Both of them are printing abnormal output

This traditional code gives me proper result

start = int(input("Enter the start of range: "))
end = int(input("Enter the end of range: "))
  
# iterating each number in list
for num in range(start, end   1):
      
    # checking condition
    if num % 2 == 0:
        print(num, end = " ")

How to print even and odd integers using Numpy arange function

CodePudding user response：

You can actually assign them to variables and just use an if statement for your code to check if the user wants to print odd elements or even elements.

start = 5
end = 25   1

# For even
np.arange(start 1, end, 2)

# For odd
np.arange(start, end, 2)

CodePudding user response：

May be this could help you

To print even :

import numpy as np
arr = [i for i in np.arange(5,25) if (i%2) == 0] 
arr

Expected Output :

[6, 8, 10, 12, 14, 16, 18, 20, 22, 24]

To print odd :

import numpy as np
arr = [i for i in np.arange(5,25) if (i%2) != 0] 
arr

Expected Output :

[5, 7, 9, 11, 13, 15, 17, 19, 21, 23]

Code is tested in Google Collab

Note : The Output will be store in List

If you want to the output in array format then store list in below format automatically it will become array

Code :

import numpy as np
arr = [i for i in np.arange(5,25) if (i%2) != 0]
arr_1 = np.array(arr)
arr_1
#type(arr_1)

Expected Output :

array([ 5,  7,  9, 11, 13, 15, 17, 19, 21, 23])

want to check the type of arr_1 just uncomment the type(arr_1) it will give you justification that it's an array : numpy.ndarray