I just want to know how to sum a specific column given the index of its column. I already do the sum, but for all column
#include <stdio.h>
#define LINE 4
#define COLUMN 3
int main()
{
int arr[LINE][COLUMN] = {
1, 2, 3,
4, 5, 6,
7, 8, 9,
10, 11, 12 };
int csum = 0;
printf("\nColumn Sum....\n");
for (int i = 0; i < LINE; i )
{
for(int j = 0; j < COLUMN; j )
{
csum = csum arr[j][i];
printf("%d | csum: %d \n", i, csum);
}
}
printf("\nSum of all the elements in column is %d\n",csum);
return 0;
}
I want to give i.e "0" for the column and it returns 22 (1 4 7 10). I tried hardcode the "j" in the in csum = csum arr[j][i]
to csum = csum arr[0][i]
but it doesn't work.
CodePudding user response:
Get rid of the column loop.
#include <stdio.h>
#define LINE 4
#define COLUMN 3
int main()
{
int arr[LINE][COLUMN] = {1,2,3,
4,5,6,
7,8,9,
10,11,12};
int csum = 0;
int column = 0; // desired column
printf("\nColumn Sum....\n");
for(int i = 0 ; i < LINE ; i )
{
csum = arr[i][column];
}
printf("\nSum of all the elements in column %d is %d\n", column, csum);
return 0;
}
You also had the row and column indexes backwards in arr[j][i]
.