I have this record:
import Data.Functor.Identity
import Control.Monad.Trans.Identity
import Data.Coerce
data Env m = Env {
logger :: String -> m ()
}
env :: Env IO
env = undefined
and this coercion function
decorate
:: Coercible (r_ m) (r_ (IdentityT m))
=> r_ m -> r_ (IdentityT m)
decorate = coerce
which is applicable to the record value without problems:
decoratedEnv :: Env (IdentityT IO)
decoratedEnv = decorate env
However, if I define the only slightly more complex record
data Env' h m = Env' {
logger' :: h (String -> m ())
}
env' :: Env' Identity IO
env' = undefined
And try to insert an IdentityT
wrapper like I did before
decoratedEnv' :: Env' Identity (IdentityT IO)
decoratedEnv' = decorate env'
I get the error:
* Couldn't match type `IO' with `IdentityT IO'
arising from a use of `decorate'
To my mind, the extra Identity
parameter taken by Env'
shouldn't stop coerce
from working. Why does coerce
fail in this case? Is there a way to make coerce
work?
CodePudding user response:
A coercion Coercible A B
does not imply a coercion Coercion (h A) (h B)
for all h
.
Consider this GADT:
data T a where
K1 :: Int -> T A
K2 :: Bool -> T B
Coercing T A
to T B
amounts to coercing Int
to Bool
, and that clearly should never happen.
We could perform that coercion only if we knew that the parameter of h
has the right role (e.g. representational
or phantom
, but not nominal
).
Now, in your specific case h
is known (Identity
), and has surely the right role, so it should work. I guess the GHC coercion system is not so powerful to handle such a "well behaved" h
while rejecting the ill-behaved ones, so it conservatively rejects everything.
Adding a type hole seems to confirm this. I tried
decoratedEnv' :: Env' Identity (IdentityT IO)
decoratedEnv' = _ decorate' @(Env' Identity)
and got the error
* Couldn't match representation of type: r_0 m0
with that of: r_0 (IdentityT m0)
arising from a use of decorate'
NB: We cannot know what roles the parameters to `r_0' have;
we must assume that the role is nominal
* In the first argument of `_', namely decorate'
In the expression: _ decorate' @(Env' Identity)
In an equation for decoratedEnv':
decoratedEnv' = _ decorate' @(Env' Identity)
The "NB:" part is right on the spot.
I also tried to insist, and force the role
type role Env' representational representational
data Env' h m = Env' {
logger' :: h (String -> m ())
}
to no avail:
* Role mismatch on variable m:
Annotation says representational but role nominal is required
* while checking a role annotation for Env'
The best workaround I could find is to unwrap/rewrap, and exploit QuantifiedConstraints
to essentially require that h
has a non-nominal
role:
decorate'
:: (forall a b. Coercible a b => Coercible (h a) (h' b))
=> Coercible m m'
=> Env' h m -> Env' h' m'
decorate' (Env' x) = Env' (coerce x)
decoratedEnv' :: Env' Identity (IdentityT IO)
decoratedEnv' = decorate' env'
Not an ideal solution, since it goes against the spirit of Coercible
. In this case, the rewrapping has only O(1) cost, but if we had, say, a list of Env' Identity IO
to convert, we would pay O(N).