I want to display the popup on the website and the scenario is like that.
- If the user visits 5 pages display the popup
- If the user stays on the website and spends 2 minutes display the popup
- If the user closes the popup it will not appear again next time.
It is working fine but I do not know how to solve problem 2 (if the user stay on the website and spend 2 minutes displaying a popup)
I tried it with local storage but did not help.
Here is the code...
var popup = '<div id="sub-popup">';
popup = '<div id="subscribe-popup" >';
popup = '<a onclick="closePopup()">×</a>';
popup = '<h1 >Subscribe here!</h1>';
popup = '<p >Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.</p>'
popup = '<a onclick="hidePopup()">Subscribe</a>';
popup = '</div>';
popup = '</div>';
function closePopup() {
$('#sub-popup').remove();
localStorage.displayPopup = 0;
}
function hidePopup() {
$('#sub-popup').remove();
localStorage.displayPopup = 0;
window.open("https://upesy.us17.list-manage.com/subscribe/post?u=4f67f99a5b6bf0f744449df73&id=45f50ab267", "_blank");
}
jQuery(document).ready(function($) {
function getCookieVal(offset) {
var endstr = document.cookie.indexOf(";", offset);
if (endstr == -1)
endstr = document.cookie.length;
return unescape(document.cookie.substring(offset, endstr));
}
function GetCookie(name) {
var arg = name "=";
var alen = arg.length;
var clen = document.cookie.length;
var i = 0;
while (i < clen) {
var j = i alen;
if (document.cookie.substring(i, j) == arg)
return getCookieVal(j);
i = document.cookie.indexOf(" ", i) 1;
if (i == 0)
break;
}
return null;
}
function SetCookie(name, value) {
var argv = SetCookie.arguments;
var argc = SetCookie.arguments.length;
var expires = (2 < argc) ? argv[2] : null;
var path = (3 < argc) ? argv[3] : null;
var domain = (4 < argc) ? argv[4] : null;
var secure = (5 < argc) ? argv[5] : false;
document.cookie = name "=" escape(value)
((expires == null) ? "" : ("; expires=" expires.toGMTString()))
((path == null) ? "" : ("; path=" path))
((domain == null) ? "" : ("; domain=" domain))
((secure == true) ? "; secure" : "");
}
function displayPopup() {
var expdate = new Date();
var visit;
expdate.setTime(expdate.getTime() (24 * 60 * 60 * 1000 * 365));
if (!(visit = GetCookie("upesy-cookie")))
visit = 0;
visit ;
SetCookie("upesy-cookie", visit, expdate, "/", null, false);
if (visit >= 4) {
if(localStorage.displayPopup != 0) {
setTimeout(function(){
$(document.body).append(popup);
SetCookie("upesy-cookie", 0);
}, 2000);
}
}
}
//window.onload = displayPopup
$(window).on("load", displayPopup);
});
CodePudding user response:
You can use setTimeout() in JavaScript.
setTimeout(() => {
// Open popup
}, 120000); // Amount of time to wait, in miliseconds
CodePudding user response:
You can store the time on beforeunload
in local storage and set a timer on page load
if (localStorage.getItem('displayPopup') !== '0') {
const openTime = Date.now();
const totalVisitTime = localStorage.getItem('totalVisitTime');
document.getElementById('container').innerHTML = totalVisitTime;
setTimeout(() => {
alert('2 Minute Timeout');
localStorage.setItem('displayPopup', '0');
localStorage.removeItem('totalVisitTime');
}, 12e4 - totalVisitTime);
window.addEventListener('beforeunload', () => {
if (localStorage.getItem('displayPopup') === '0') return;
localStorage.setItem(
'totalVisitTime',
totalVisitTime Date.now() - openTime
);
});
}
<div id="container"></div>
<iframe name="sif1" sandbox="allow-forms allow-modals allow-scripts" frameborder="0"></iframe>