I currently have a nested dictionary like:

[{'rule': {'actions': {'allow': False}, 'dl_type': 2048, 'ipv4_dst': '192.168.50.0/24', 'ipv4_src': '192.168.50.20'}}, {'rule': {'actions': {'allow': False}, 'dl_type': 2048, 'ipv4_dst': '192.168.50.0/24', 'ipv4_src': '192.168.50.10'}}, {'rule': {'actions': {'allow': True}}}]

I want to remove this from my nested dictionary:

{'rule': {'actions': {'allow': False}, 'dl_type': 2048, 'ipv4_dst': '192.168.50.0/24', 'ipv4_src': '192.168.50.10'}}

How would I do something like this? I don't think I can remove the dictionary based on the key because it looks like there are multiple dictionaries that contain the same keys. It sounds like it should be simple, but I can't seem to remove that dictionary and the nested dictionaries inside of it (maybe because I'm burned out for the day). Any help is greatly appreciated on this!

CodePudding user response：

It looks like the difference between the bolded element and the previous element is the value for ipv4_src i.e., 192.168.50.10, therefore you could use a list comprehension to remove the dictionary with that:

org_list = [{
    'rule': {
        'actions': {
            'allow': False
        },
        'dl_type': 2048,
        'ipv4_dst': '192.168.50.0/24',
        'ipv4_src': '192.168.50.20'
    }
}, {
    'rule': {
        'actions': {
            'allow': False
        },
        'dl_type': 2048,
        'ipv4_dst': '192.168.50.0/24',
        'ipv4_src': '192.168.50.10'  # this is the difference
    }
}, {
    'rule': {
        'actions': {
            'allow': True
        }
    }
}]

new_list = [
    d for d in org_list if d['rule'].get('ipv4_src', '') != '192.168.50.10'
]

print(new_list)

Output:

[{'rule': {'actions': {'allow': False}, 'dl_type': 2048, 'ipv4_dst': '192.168.50.0/24', 'ipv4_src': '192.168.50.20'}}, {'rule': {'actions': {'allow': True}}}]