How to exclude certain property from the list in NodeJS-CodePudding

I'm having the below list and I would like to add only these property names PRODUCT_TYPE, PRODUCT_TERM, PRODUCT_ID in myProduct. I want to ignore rest of the properties - I've around 100 properties and want to filter only a few of them from myProduct

Please find my code below:

const obj = {
  myProduct: [
    {
      name: "PRODUCT_PRICE",
      value: "234.324",
    },

    {
      name: "PRODUCT_NAME",
      value: "Insurance",
    },
    {
      name: "PRODUCT_TYPE",
      value: "Life",
    },
    {
      name: "PRODUCT_TERM",
      value: "Long",
    },
    {
      name: "PRODUCT_ID",
      value: "AP3232343JKD",
    },
    {
      name: "PRODUCT_ENABLED",
      value: "TRUE",
    },
  ],
};

const allowedNames = [
  'PRODUCT_TYPE',
  'PRODUCT_TERM',
  'PRODUCT_ID'
];

const updateCertainProperties = {
  PRODUCT_ID: "app.productID",
  PRODUCT_ENABLED: "app.product.enabled"
};

const productName = "testProduct_3234dfasfdk3msldf23";
const environment = obj.myProduct.map((o) => {
  obj.myProduct.filter(product => allowedNames.includes(product.name));
  if (updateCertainProperties[o.name]) o.name = updateCertainProperties[o.name];
  if (o.name === "PRODUCT_NAME") o.value = productName;    
  return obj.myProduct;
  
});

console.log(obj.myProduct)

Expected output:

[
  { name: 'PRODUCT_NAME', value: 'testProduct_3234dfasfdk3msldf23' },
  { name: 'PRODUCT_TYPE', value: 'Life' },
  { name: 'PRODUCT_TERM', value: 'Long' },
  { name: 'app.productID', value: 'AP3232343JKD' },
  { name: 'app.product.enabled', value: 'TRUE' }
]

Can someone please help me how can I achieve this? Appreciated your help in advance!

CodePudding user response：

You can create an array of allowed names and filter them out using includes()

css just for prettier output

const obj = {
        myProduct: [
            {
                name: "PRODUCT_NAME",
                value: "Insurance",
            },
            {
                name: "PRODUCT_TYPE",
                value: "Life",
            },
            {
                name: "PRODUCT_TERM",
                value: "Long",
            },
            {
                name: "PRODUCT_ID",
                value: "AP3232343JKD",
            },
            {
                name: "PRODUCT_ENABLED",
                value: "TRUE",
            },
        ],
    };

    const allowedNames = [
        'PRODUCT_TYPE',
        'PRODUCT_TERM',
        'PRODUCT_ID'
    ];

    obj.myProduct = obj.myProduct.filter(product => allowedNames.includes(product.name));

    console.log(obj.myProduct);

.as-console-wrapper {
  max-height: unset !important;
  top: 0;
}

CodePudding user response：

It sounds like you're describing filtering an array, not "excluding properties". You have an array of objects, with each object consisting of a name property and value property. And you only want objects with specific values in their name property.

Using .filter on the array, it might look something like this:

obj.myProduct = obj.myProduct.filter(p => (
  p.name === 'PRODUCT_TYPE' ||
  p.name === 'PRODUCT_TERM' ||
  p.name === 'PRODUCT_ID'));

This would filter out all elements of the array which don't match the supplied condition.