Here is my code:
const string = `1
00:01:46,356 --> 00:01:49,893
test test test test
2
00:01:50,794 --> 00:01:54,998
test test test red test test
3
00:01:55,199 --> 00:01:58,267
test test red`;
const match = st.split('\n\n').find((e) => e.includes('red'));
console.log(match);
the problem is it returns only the first occurance (the word "red" in 2nd sentence) while there is another "red" in the last sentence. What should I do to get all occurrences?
CodePudding user response：
Using find:
returns the value of the first element in the provided array that satisfies the provided testing function
Instead of find, you can use filter:
const match = string.split('\n\n').filter((e) => e.includes('red'));
const string = `1
00:01:46,356 --> 00:01:49,893
test test test test
2
00:01:50,794 --> 00:01:54,998
test test test red test test
3
00:01:55,199 --> 00:01:58,267
test test red`;
const match = string.split('\n\n').filter((e) => e.includes('red'));
console.log(match);CodePudding user response：
Just use filter instead of find.
const st = `1
00:01:46,356 --> 00:01:49,893
test test test test
2
00:01:50,794 --> 00:01:54,998
test test test red test test
3
00:01:55,199 --> 00:01:58,267
test test red`;
const match = st.split('\n\n').filter((e) => e.includes('red'));
console.log(match);