Find "n" in a list full of strings-CodePudding

I'm looking to go through a list and find any element with a number.

This is what i got so far

list = ['Alvarez, S', 'Crawford, B', 'Fury, 8', 'Mayweather, F', 'Lopez, 44']

num = '8'

for s in home_pitchers:
    if num in s:
        print(s)

print(ex)
>>> Fury, 8

What I'm looking to do is to have num be 0 - 9. I thought about using '[^0-9]' but that didn't work.

Ultimately I'm looking to print out this

print
>>> Fury, 8
>>> Lopez, 44

Just a heads up, I'm pretty new to coding so some concept might go over my head

CodePudding user response：

You can use isdigit method with any function. The isdigit method return True if the string is a digit string, False otherwise.

>>> lst = ['Alvarez, S', 'Crawford, B', 'Fury, 8', 'Mayweather, F', 'Lopez, 44']
>>>
>>> for s in lst:
...     if any(char.isdigit() for char in s):
...             print(s)
...
Fury, 8
Lopez, 44

CodePudding user response：

Using the re library:

import re

lst = ['Alvarez, S', 'Crawford, B', 'Fury, 8', 'Mayweather, F', 'Lopez, 44']

list(filter(lambda x:re.match(".*[0-9] $",x), lst))

OUTPUT:

['Fury, 8', 'Lopez, 44']

The pattern matches any string ending with one or more numbers.