I am writing here for the first time, and I was given the following problem. For example, I have the following array:
const input = [
{
id: 1,
date: "01-01-2021",
source: "TT",
metrics: { conversions: 10, cpl: 3 },
},
{
id: 2,
date: "01-01-2021",
source: "TT",
metrics: { conversions: 15, cpl: 3 },
},
{
id: 3,
date: "01-01-2021",
source: "FB",
metrics: { conversions: 15, cpl: 4 },
},
{
id: 4,
date: "01-01-2021",
source: "FB",
metrics: { conversions: 15, cpl: 4 },
},
{
id: 5,
date: "02-01-2021",
source: "TT",
metrics: { conversions: 5, cpl: 2 },
},
{
id: 6,
date: "02-01-2021",
source: "TT",
metrics: { conversions: 15, cpl: 2 },
},
{
id: 7,
date: "02-01-2021",
source: "FB",
metrics: { conversions: 25, cpl: 1 },
},
{
id: 8,
date: "02-01-2021",
source: "FB",
metrics: { conversions: 30, cpl: 1 },
},
];
And I need to get an array grouped by date and source and the value will be the sum of all its values for a specific date, for example as the result below:
const output = [
{
date: "01-01-2021",
TT: 25,
FB: 30,
},
{
date: "02-01-2021",
TT: 20,
FB: 55,
},
];
In my solution, I find unique keys and dates, but do not understand what to do next. Can you help me? Sample code:
const result = input.reduce((acc, current) => {
const dateItem = acc.find((item) => item.date === current.date);
const sources = input.map((item) => item.source).filter((value, index, self) => self.indexOf(value) === index);
if (dateItem) {
return [...acc.filter((i) => i.date !== current.date), { ...dateItem }];
}
return [...acc, { date: current.date }];
}, []);
CodePudding user response:
Simple reduce loop using the date as a key. After you get it all combined, you can use values to get the array.
const input = [{
id: 1,
date: "01-01-2021",
source: "TT",
metrics: {
conversions: 10,
cpl: 3
},
},
{
id: 2,
date: "01-01-2021",
source: "TT",
metrics: {
conversions: 15,
cpl: 3
},
},
{
id: 3,
date: "01-01-2021",
source: "FB",
metrics: {
conversions: 15,
cpl: 4
},
},
{
id: 4,
date: "01-01-2021",
source: "FB",
metrics: {
conversions: 15,
cpl: 4
},
},
{
id: 5,
date: "02-01-2021",
source: "TT",
metrics: {
conversions: 5,
cpl: 2
},
},
{
id: 6,
date: "02-01-2021",
source: "TT",
metrics: {
conversions: 15,
cpl: 2
},
},
{
id: 7,
date: "02-01-2021",
source: "FB",
metrics: {
conversions: 25,
cpl: 1
},
},
{
id: 8,
date: "02-01-2021",
source: "FB",
metrics: {
conversions: 30,
cpl: 1
},
},
];
const results = Object.values(input.reduce((o, data) => {
o[data.date] = o[data.date] || { date: data.date };
o[data.date][data.source] = (o[data.date][data.source] || 0) data.metrics.conversions;
return o;
}, {}));
console.log(results);
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CodePudding user response:
Array.reduce
with Object.values
will give the result.
const input = [
{ id: 1, date: "01-01-2021", source: "TT", metrics: { conversions: 10, cpl: 3 }, },
{ id: 2, date: "01-01-2021", source: "TT", metrics: { conversions: 15, cpl: 3 }, },
{ id: 3, date: "01-01-2021", source: "FB", metrics: { conversions: 15, cpl: 4 }, },
{ id: 4, date: "01-01-2021", source: "FB", metrics: { conversions: 15, cpl: 4 }, },
{ id: 5, date: "02-01-2021", source: "TT", metrics: { conversions: 5, cpl: 2 }, },
{ id: 6, date: "02-01-2021", source: "TT", metrics: { conversions: 15, cpl: 2 }, },
{ id: 7, date: "02-01-2021", source: "FB", metrics: { conversions: 25, cpl: 1 }, },
{ id: 8, date: "02-01-2021", source: "FB", metrics: { conversions: 30, cpl: 1 }, },
];
const output = input.reduce((acc, curr) => {
if (acc[curr.date]) {
acc[curr.date][curr.source] = (acc[curr.date][curr.source] || 0) curr.metrics.conversions;
} else {
acc[curr.date] = {
date: curr.date,
[curr.source]: curr.metrics.conversions
}
}
return acc;
}, {});
console.log(Object.values(output));
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