Why does passing an int of 3 give me two rows with numpy.zeros(3)?-CodePudding

The int passed makes a 3x3, 2-D array.

np.zeros(3)

But it makes a 3 column array with 2 rows.

[0. 0. 0.]
[0. 0. 0.]

What's the reason behind this? And when I pass a shape of (3,3) to np.zero()'s shape it makes even less sense. 2 of them? Looking into a duplication issue here.

[[0. 0. 0.]               
 [0. 0. 0.]               
 [0. 0. 0.]]              
[[0. 0. 0.]               
 [0. 0. 0.]               
 [0. 0. 0.]]

CodePudding user response：

Normal output:

In [430]: np.zeros(3)
Out[430]: array([0., 0., 0.])
In [431]: np.zeros((3,3))
Out[431]: 
array([[0., 0., 0.],
       [0., 0., 0.],
       [0., 0., 0.]])

CodePudding user response：

The name of the file was originally array.py. Changing this name fixed the issue. This post helped. link