import requests
from datetime import datetime

gg = []

now = datetime.now()
current_time = now.strftime("%Y-%m-%dT%H:%M:%S")

url = ("https://sportsbook-sm-distribution-api.nsoft.com/api/v1/events?deliveryPlatformId=3&dataFormat={"default":"object","events":"array","outcomes":"object"}&language={"default":"sr-Latn","events":"sr-Latn","sport":"sr-Latn","category":"sr-Latn","tournament":"sr-Latn","team":"sr-Latn","market":"sr-Latn"}&timezone=Europe/Belgrade&company={}&companyUuid=4dd61a16-9691-4277-9027-8cd05a647844&filter[sportId]=3&filter[from]={}&sort=categoryPosition,categoryName,tournamentPosition,tournamentName,startsAt&offerTemplate=WEB_OVERVIEW&shortProps=1").format(current_time)

response = requests.get(url)
matches = response.json()
print(matches) #This is my json document

I am trying to scrape odds from betting site. I am pretty new to python and I need some help.

Some kind of "Odd id" is stored in key "b". So basically for every match in this json file, if match contains key "b" with value 2763, i want to scrape value of key "g" and store it in my list "gg"(in key "g" value is odd that i want to scrape). But if match doesn't contains key "b" with value 2763, for that match I want to append only one time "1.00" to list "gg".

for match in matches:
    mat = matches['data']['events']
    for s in range(len(mat)):
        o = mat[s]['o']
        for element in o:
            h = o[element]['h']
            for x in h:
                if h[x]['b'] == 2763:
                gg.append(h[x]['g'])

With this command i can scrape odds but i don't how to append "1.00" to GG if match doesn't have 'b':2763 (oddid)

CodePudding user response：

i haven't verified your code but i'm assuming it works and you understand what it does. what you need is a flag. a flag is just a boolean (True/False), let's name it has_2763. you just have to reset it at each match start

for match in matches:
    mat = matches['data']['events']
    for s in range(len(mat)):
        has_2763 = False
        o = mat[s]['o']
        for element in o:
            h = o[element]['h']
            for x in h:
                if h[x]['b'] == 2763:
                    gg.append(h[x]['g'])
                    has_2763 = True
        if not has_2763:
            gg.append("1.00")

CodePudding user response：

From what I can understand from your problem. This should be the solution.

   json = {
        'b': 2763,
        'g': 'odd number'
    }
    
    x = 'b'
    y = 2763
    gg = []
    
    for key, value in json.items():
        if x == key and y == value:  # if finds b: 2763
            gg.append(json.get('g'))
        elif x == key and y != value:
            gg.append(1.00)
            break

you can reduce the number of lines using comprehension.