python, exponentiaiton with 'def' and 'for-loop'-CodePudding

input:

numbers = [1,2,3]
increment = 5

Expected output:

[1, 32, 243]

Result with my code:

1
32
243

Code:

def power(x, y):

    if (y == 0): return 1
    elif (int(y % 2) == 0):
        return (power(x, int(y / 2)) *
            power(x, int(y / 2)))
    else:
        return (x * power(x, int(y / 2)) *
                power(x, int(y / 2)))

for number in numbers:
    exponentiation = power(number,increment)
    print(exponentiation)

I'm trying to find the square root of the numbers in a list without pow() and '**' functions. I've found the square root of each number, but I'm wondering how to put them in a list.

CodePudding user response：

You are printing the exponentiations, but instead you want to output the list. This is what you want to do:

# your function code above

answer = []
for number in numbers:
    exponentiation = power(number,increment)
    answer.append(exponentiation)

print(answer)

This will give:

[1, 32, 243]

CodePudding user response：

You should make an empty list before the for-loop, then inside the for-loop, instead of printing each number, append it to the list. Then at the end, print the list.

def power(x, y):

    if (y == 0): return 1
    elif (int(y % 2) == 0):
        return (power(x, int(y / 2)) *
            power(x, int(y / 2)))
    else:
        return (x * power(x, int(y / 2)) *
                power(x, int(y / 2)))

output_list = []

for number in numbers:
    exponentiation = power(number,increment)
    output_list.append(exponentiation)

print(output_list)

CodePudding user response：

You can use single line for loops -

exponentiation = [power(number,increment) for number in numbers]
print(exponentiation)
#[1,32,243]

CodePudding user response：

you can use the pow function of the python library and append value in the list and print list instead of individual value

numbers = [1,2,3]
increment = 5
l=[]
for i in numbers:
    ex=pow(i,increment )
    l.append(ex)
print(l)

output

[1, 32, 243]