Creating a list of dictionaries with numerous key value pairs-CodePudding

I have multiple lists that I need to combine into a list of dictionaries with multiple key value pairs wherein the value could in itself contain a list - so for example:

namesIDs = [1, 2, 3, 4, 5]
namesList = ['jacksparrow', 'aragron', 'harrypotter', 'bilbo', 'einstein']
address = ['addr1', 'addr2', 'addr3', 'addr4', 'addr5']
parentsIDs = [11, 12, 13, 14, 21, 22, 23, 24, 31, 32, 33, 34, 41, 42, 43, 44, 51, 52, 53, 54] 
parentsNames = ['Teague', 'MrsT', 'gPaT', 'gMaT', 'Arathorn', 'Gilraen', 'gPaAg', 'gMaAg', 'James', 'Lily', 'gPaHp', 'gMaHp', 'Bungo', 'Belladona', 'gPaB', 'gMaB', 'Herman', 'Pauline', 'Abraham', 'Helene']

The output I'm expecting is:

[{'nameIDs': 1, 'namesList': 'jacksparrow', 'address': 'addr1', 'parentsIDs': [11,12,13,14], 'parentsNames': ['Teague', 'MrsT', 'gPaT', 'gMaT']},
 {'nameIDs': 2, 'namesList': 'aragorn', 'address': 'addr2', 'parentsIDs': [21,22,23,24], 'parentsNames': ['Arathorn', 'Gilraen', 'gPaAg', 'gMaAg']},
 {'nameIDs': 3, 'namesList': 'harrypotter', 'address': 'addr3', 'parentsIDs': [31,32,33,34], 'parentsNames': ['James', 'Lily', 'gPaHp', 'gMaHp']},
 {'nameIDs': 4, 'namesList': 'bilbo', 'address': 'addr4', 'parentsIDs': [41,42,43,44], 'parentsNames': ['Bungo', 'Belladona', 'gPaB', 'gMaB']},
 {'nameIDs': 5, 'namesList': 'einstein', 'address': 'addr5', 'parentsIDs': [51,52,53,54,55,56], 'parentsNames': ['Bungo', 'Belladona', 'gPaB', 'gMaB', 'babyA', 'babyB']}
]

NOTICE the last item parentsIDs/parentsNames are LONGER than the rest. I've tried using zip and dict comprehension but it doens't work/make sense to me. Any help is greatly appreciated!

>>> namesIDs = [1, 2, 3, 4, 5]
>>> namesList = ['jacksparrow', 'aragron', 'harrypotter', 'bilbo', 'einstein']
>>> [dict(zip(('NameID', 'Name'), item )) for item in namesList]
[{'NameID': 'j', 'Name': 'a'}, {'NameID': 'a', 'Name': 'r'}, {'NameID': 'h', 'Name': 'a'}, {'NameID': 'b', 'Name': 'i'}, {'NameID': 'e', 'Name': 'i'}]

EDIT: PLEASE note that parentsIDs and parentsNames might be arbitrarily long and not necessarily be equal to each other in length. Both solutions below yield incorrect answers. I've updated the full expected output to prevent ambiguity.

CodePudding user response：

You can create list of lists for last 2 lists and then use zip and list_comprehension.

namesIDs = [1, 2, 3, 4, 5]
namesList = ['jacksparrow', 'aragron', 'harrypotter', 'bilbo', 'einstein']
address = ['addr1', 'addr2', 'addr3', 'addr4', 'addr5']
parentsNames = ['Teague', 'MrsT', 'gPaT', 'gMaT', 'Arathorn', 'Gilraen', 'gPaAg', 'gMaAg', 'James', 'Lily', 'gPaHp', 'gMaHp', 'Bungo', 'Belladona', 'gPaB', 'gMaB', 'Herman', 'Pauline', 'Abraham', 'Helene']
parentsIDs = [11, 12, 13, 14, 21, 22, 23, 24, 31, 32, 33, 34, 41, 42, 43, 44, 51, 52, 53, 54] 

parentsIDs = [parentsIDs[i:i  int(len(parentsIDs)/len(namesIDs))] for i in range(0,len(parentsIDs),int(len(parentsIDs)/len(namesIDs)))]
parentsNames = [parentsNames[i:i  int(len(parentsNames)/len(namesIDs))] for i in range(0,len(parentsNames),int(len(parentsNames)/len(namesIDs)))]

final_dict = [{"nameIDs":n,"namesList":nl, "address":ad, 'parentsIDs':pid, 'parentsNames':pn} for n,nl,ad,pid,pn in zip(namesIDs,namesList,address,parentsIDs,parentsNames)]

print(final_dict)

CodePudding user response：

You can use list slicing inside the following list comprehension.

out = [{'nameIDs': a, 'namesList': b, 'address': c, 
        'parentsIDs': parentsIDs[d:d len(namesIDs)-1], 
        'parentsNames': parentsNames[e:e len(namesIDs)-1]} 
       for a,b,c,d,e in zip(namesIDs, namesList, address, 
                            range(0, len(parentsIDs), len(parentsIDs) // len(namesIDs)), 
                            range(0, len(parentsNames), len(parentsNames) // len(namesIDs)))]

Output:

[{'nameIDs': 1,
  'namesList': 'jacksparrow',
  'address': 'addr1',
  'parentsIDs': [11, 12, 13, 14],
  'parentsNames': ['Teague', 'MrsT', 'gPaT', 'gMaT']},
 {'nameIDs': 2,
  'namesList': 'aragron',
  'address': 'addr2',
  'parentsIDs': [21, 22, 23, 24],
  'parentsNames': ['Arathorn', 'Gilraen', 'gPaAg', 'gMaAg']},
 {'nameIDs': 3,
  'namesList': 'harrypotter',
  'address': 'addr3',
  'parentsIDs': [31, 32, 33, 34],
  'parentsNames': ['James', 'Lily', 'gPaHp', 'gMaHp']},
 {'nameIDs': 4,
  'namesList': 'bilbo',
  'address': 'addr4',
  'parentsIDs': [41, 42, 43, 44],
  'parentsNames': ['Bungo', 'Belladona', 'gPaB', 'gMaB']},
 {'nameIDs': 5,
  'namesList': 'einstein',
  'address': 'addr5',
  'parentsIDs': [51, 52, 53, 54],
  'parentsNames': ['Herman', 'Pauline', 'Abraham', 'Helene']}]