How to convert all date objects from a list into datetime objects-CodePudding

I have this list:

myList = [datetime.date(2021, 1, 1), datetime.date(2021, 2, 1), datetime.date(2021, 3, 1)]

I want to use a loop to replace all the date objects in this list with datetime objects. Any solutions?

CodePudding user response：

Just use datetime constructor:

import datetime

l1 = [datetime.date(2021, 1, 1), datetime.date(2021, 2, 1), datetime.date(2021, 3, 1)]
l2 = [
    datetime.datetime(year=d.year, month=d.month, day=d.day)
    for d in l1
]

print(l2)

CodePudding user response：

datetime.datetime.combine can be used to create a datetime.datetime from a datetime.date and a datetime.time. Pass datetime.time.min to get the start of the day

import datetime
myList = [datetime.date(2021, 1, 1), datetime.date(2021, 2, 1), datetime.date(2021, 3, 1)]

result = [datetime.datetime.combine(d, datetime.time.min) for d in myList]

CodePudding user response：

for date in myList:
    date = datetime.datetime(date.year, date.month, date.day)

if you want to use a for

CodePudding user response：

You can use help(datetime.date) and help(datetime.datetime) to find that date has attributes for year, month and day, and that datetime.datetime takes those values when its created. So make a list comprehension that does that

>>> import datetime
>>> myList = [datetime.date(2021, 1, 1), datetime.date(2021, 2, 1), datetime.date(2021, 3, 1)]
>>> newList = [datetime.datetime(d.year, d.month, d.day) for d in myList]
>>> newList
[datetime.datetime(2021, 1, 1, 0, 0), datetime.datetime(2021, 2, 1, 0, 0), datetime.datetime(2021, 3, 1, 0, 0)]